In order to estimate the average time spent on the computer terminals per student at a local university, data were collected from a sample of 81 business students over a one-week period. Assume the population standard deviation is 1.2 hours. Refer to Exhibit 8-1. With a .95 probability, the margin of error is approximately.

Margin of error =

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 81

Alpha, α = 0.05

Population standard deviation, σ = 1.2 hours

Margin of error formula:

Putting the values, we get

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²