Car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 12 ft/sec2. How long before the car stops? Round your answer to one decimal place.

Using the motion equation, the distance traveled by the car comes to rest would be 66.67 metres.

Using the relation :

Hence, we have ;

0² = 40² - 2(12)(s)

0 = 1600 - 24s

24s = 1600

Divide both sides by 24

s = 1600/24

s = 66.67 meters.

Hence, the car would travel a distance of 66.67 meters before stopping.

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66.7 feet

Step-by-step explanation:

v² = u² + 2as

0² = 40² + 2(-12)(so

1600 = 24s

s = 66⅔ or 66.7

20

step-by-step explanation:

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!