Suppose that a particle following the given path c(t) flies off on a tangent at t = t0. Compute the position of the particle at the given time t1. c(t) = (2t2, t3 − 4t, 0), where t0 = 3, t1 = 4

(30,35,0)

Step-by-step explanation:

We are given that

The velocity of particle,

Substitute

The tangent line at t=3 is given by

Now, substitute t=4

Hence, the position of particle  at =(30,35,0)

b

step-by-step explanation: