A student figures that he has a 4141% chance of being let out of class late. If he leaves class late, there is a 3030% chance that he will miss his train. What is the probability that he gets out of class late and misses the train?

12.3%

Step-by-step explanation:

In this case, despite being different events, they are dependent on each other, therefore the final probability would be the multiplication of both probabilities.

So let L be the probability of being late that is equal to 41% and let T be the probability that the train will leave you and is equal to 30%.

That is to say:

L = 41% = 0.41

T = 30% = 0.3

So:

P = L * T

P = 0.41 * 0.3 = 0.123

So it means that the final probability is 12.3%

what is the answer?