Find the PERIMETER and area of the figure.
Perimeter=110ft
area=600ft²

please break this down for me so I can understand it!! I'm stuck on perimeter mainly

The answer to your question is Perimeter = 110 ft; Area = 600 ft²

Step-by-step explanation:

To find the perimeter, find the hypotenuse of each triangle.

a) Hypotenuse of the large triangle

         c² = 18² + 24²

         c² = 324 + 576

         c² = 900

         c = 30 ft

b) Hypotenuse of the small triangle

        c² = 7² + 24²

             = 49 + 574

             = 625

             = 25 ft

c) Perimeter = (2 x 30) + (2 x 25)

                    = 60 + 50

                    = 110 ft

Area

a) Calculate the area of the large triangle

Area = base x height

         = 1/2 (18)(24)

         = 216 ft²

b) Calculate the area of the small triangle

Area = 1/2 (7)(24)

        = 84 ft²

c) Total area = 2(216) + 2(84)

                     = 432 + 168

                     = 600 ft²

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.