What are the solutions of 4x^2+16x=9

Step-by-step explanation:

Ethan, this is a quadratic equation.  We should rewrite this in standard quadratic form:  4x^2 + 16x - 9 = 0.  Let's use the quadratic formula approach to solve this:

The coefficients of x are a = 4, b = 16 and c = -9.  Thus, the discriminant is

b^2 - 4ac, or 16^2 - 4(4)(-9), or 256 - 144, or 112.

The two solutions are real and are as follows:

       -16 ± √112            -16 ± √(16*7)         -16 ± 4√7

x =   = =

            2(4)                            8                        8

Or, after simplification,

       -4 ± √7

x =

             2

my answer is$ 12

step-by-step explanation:

because 15 -2=12

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true