X^3+7x^2-36x 3 +7x 2 −36x, cubed, plus, 7, x, squared, minus, 36 The polynomial above has zeros at -6−6minus, 6 and 222. If the remaining zero is zzz, then what is the value of -z−zminus, z?

Step-by-step explanation:

Equation:

x^3 + 7x^2 - 36

Given that:

x1 = -6

x2 = 2

x3 = z

Let the zeros be,

x + 6, x - 2

Multiplying both of these factors ,

(x + 6) × (x - 2)

x^2 + 6x - 2x - 12

= x^2 + 4x - 12

Dividing the polynomial, x^3 + 7x^2 - 36 with the above quadratic equation,

We get:

x^3 + 7x^2 - 36 ÷ x^2 + 4x - 12

= x + 3

z; x + 3 = 0

x = -3

z = -3

-z = 3

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