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Note: Figure not drawn to scale
If a = 33 in and b = 44 in, which of the following is closest to the area of the window?
A.
2,307.3 in2
B.
2,904 in 2
C. 1,452 in2
D.
1,879.65 in?

Work Shown:

The rectangle has area 33*44 = 1452 square inches. This is just part of the answer. The semicircle up top must be accounted for as well.

This semicircle has a radius of r = a/2 = 33/2 = 16.5 inches

The area of the semicircle is (1/2)*pi*r^2 = (1/2)*3.14*(16.5)^2 = 427.4325

This adds to the area of the rectangle to get 427.4325+1452 = 1,879.4325

This is fairly close to choice D, though we're a bit off.

The reason for the error is because of how pi = 3.14 is an approximation. A more accurate version is pi = 3.1415926535898

Therefore, the area of the semicircle is closer to

(1/2)*pi*r^2 = (1/2)*3.1415926535898*(16.5)^2 = 427.649299969911

then we add on the rectangle area:

427.649299969911+1452 = 1,879.64929996991

that rounds to 1,879.65

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step-by-step explanation:

4x and 6y

im not sure though