Points P, Q, and R are shown on the number line. What is the distance between point P (-50) and point R (50)?
a- 50
b- 75
c- 100
d- 125

Work Shown:

Let's make point Q to be at 0 on the number line. The distance from P (-50) to Q (0) is 50 units. The distance from Q to R (50) is also 50 units. These distances add to 50+50 = 100.

Alternative method:

You can subtract the coordinates of P and R, and then use absolute value to ensure the result is positive

|P - R| = |-50 - 50| = |-100| = 100

or

|R - P| = |50 - (-50)| = |50 + 50| = |100| = 100

Either way, the answer is 100

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

true

step-by-step explanation: