When playing roulette at a casino, a gambler is trying to decide whether to bet $20 on the number 34 or to bet $20 that the outcome is any one of the three possibilities 00 comma 0 comma or 1 . The gambler knows that the expected value of the $20 bet for a single number is negative $ 1.05 . For the $20 bet that the outcome is 00 comma 0 comma or 1 , there is a probability of StartFraction 3 Over 38 EndFraction of making a net profit of $80 and a StartFraction 35 Over 38 EndFraction probability of losing $20 .a. Find the expected value for the $20 bet that the outcome is 00 comma 0 comma or 1 .b. Which bet is better: a $20 bet on the number 34 or a $20 bet that the outcome is any one of the numbers 00 comma 0 comma or 1 ? Why?

a. -$12.11

b. Bet on number 34 is better. Has the highest expected value  of the two.

Step-by-step explanation:

a. The probability of a net profit of $80 is 3/38, and of a $20 loss is 35/38. Expected value  is calculated as the summation of both expectations:

Hence, the expected value is -12.11(a loss).

b. We calculate the expected value of 34 to determine which is better;

-From the question, E(X=34)= -$1.05,

-From a above, E(X=(00,0,1))= -$12.11

#-$1.05 is greater than -$12.11( by $11.06).

-Hence, it's better to bet on number 34 since it has the highest expected value of the two.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3