F(x)=3x^2+7x and g(x)=2x^2-x-1 find (f+g)(x)

(f+g)(x) is .

Step-by-step explanation:

Here we have , f(x)=3x^2+7x and g(x)=2x^2-x-1 or . We need to find (f+g)(x) :

We know that (f+g)(x) = f(x)+g(x) as sum of functions is equivalent to normal addition in Arithmetic . Let's find out (f+g)(x):

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Therefore, f(x)=3x^2+7x and g(x)=2x^2-x-1 or and (f+g)(x) is .

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

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step-by-step explanation:

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