A manager forecasts that 150 guests will be served tomorrow. The manager knows that one server can provide high quality service for 30 guests and one cook can prepare high quality food for 60 guests. How many servers and cooks should be scheduled for tomorrow?

5 servers and 3 cooks(since a person doesn't exist in fraction)

Step-by-step explanation:

From the question provided above, the manager(who is obviously organizing some kind of party or get-togethers) is expecting a hindered and fifty guests in total .

And it also says that if a server can handle 30 guests and 150,how many of them are need?

Let X be number of servers needed:

X= 150/30 = 5 servers

AND

If a single cook can prepare meals for 60 guests,the number of cooks required to cover for 150 guest will be:

X= 150/60 = 2.5,but since a fraction of a human doesn't exist, we have to say that the manager needs 3 cooks(2 of them will handle a total of 120 guests and the other cook handles the 30 guests)

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

is should be y = 5x

step-by-step explanation:

correct me if im wrong