Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-1, -6),A(−1,−6),A, left parenthesis, minus, 1, comma, minus, 6, right parenthesis, comma B(-1,7)B(−1,7)B, left parenthesis, minus, 1, comma, 7, right parenthesis, C(1, 7)C(1,7)C, left parenthesis, 1, comma, 7, right parenthesis, and D(1, -6)D(1,−6)D, left parenthesis, 1, comma, minus, 6, right parenthesis.
Given these coordinates, what is the length of side ABABA, B of this rectangle?

13 units

Step-by-step explanation:

Rectangle ABCD has coordinates A(-1,-6), B(-1,7), C(1,7), D(1,-6)

We want to find the length of AB.

We use the absolute value method to find the length of AB.

Since the first coordinates are the same for A(-1,-6) and B(-1,7).

The distance is given by;

The length of AB is 13 units.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: