2y-3[3-4(y-5)+2(1-3y)]

- 75 - 32y

Step-by-step explanation:

2y-3[3-4(y-5)+2(1-3y)]

= 2y - 3(3 - 4y + 20 + 2 - 6y)

= 2y - 3(25 - 10y)

= 2y - 75 - 30y

= - 75 - 32y

Brainliest???

Step-by-step explanation:

2y-3[3-4(y-5)+2(1-3y)]  = 2y - 3[ 3 - 4*y - (-4)*5 + 2*1 -2*3y]

    = 2y -3[ 3- 4y+ 20+ 2- 6y]

= 2y - 3[ 3+20+2 -4y-6y]             {bring the like terms together}

=2y- 3 [25 - 10y]

=2y - 3*25 - (-3)*10y

= 2y - 75 + 30y

= 32y - 75

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6