A tour bus normally leaves for its destination at 5:00 p. m. for a 200 mile trip. This week however, the bus leaves at 5:40 p. m. To arrive on time, the driver drives 10 miles per hour faster than usual. What is the bus’s usual speed?

The usually speed of the bus is 50 miles/h.

Step-by-step explanation:

Let the usual speed of the bus be x mile/hour.

We know that

The bus travels 200 miles.

To reach its destination it takes time h

This week however the bus leaves at 5:40.

The bus late 40 minutes

Now the speed of the bus is = (x+10) miles/h

The new time to reach the destination is h

According to the problem,

⇒2(x²+10x)=200×10×3

⇒x²+10x = 3000

⇒x²+10x -3000=0

⇒x²+60x-50x-3000=0

⇒x(x+60)-50(x+60)=0

⇒(x+60)(x-50)=0

⇒x= -60,50

∴x=50 [since speed does not negative]

The usually speed of the bus is 50 miles/h.

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.