Alina fully simplifies this polynomial and then writes it in standard form. xy2 – 2x2y + 3y3 – 6x2y + 4xy2 If Alina wrote the last term as 3y3, which must be the first term of her polynomial in standard form? xy2 5xy2 –8x2y –2x2y

-8

Step-by-step explanation:

I will rewrite your polynomial:

As we can see it has five terms so you can merge first and last terms: = 5  (1)

and second and fourth terms:  

= -8 (2)

Thus, standard form of polynomial is: (1) + (2) + the third term:

-8 + 5- 3

So the first term of her polynomial in standard form is -8

Step-by-step explanation:

In the given polynomial

To simplify, first we collect like terms

Then adding up the like terms

A number is in standard form when it is arranged in ascending or descending order of a variable. Since is the last term, it is arranged in ascending order of y.

Therefore:

in standard form.

The first term is

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

36

step-by-step explanation: