Point P is on segment AB such that AP:PB is 4:5. If A has coordinates (4,2), and B has coordinates (22,2), determine and state the coordinates of P.

The coordinates of P are (12, 2).

Solution:

Given data:

 and

P(x, y) is the point on the line segment AB.

AP : PB = m : n = 4 : 5.

That is m = 4 and n = 5.

Section formula:

P(x, y) = (12, 2)

Hence the coordinates of P are (12, 2).

boxplot e is the answer

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)