1) f(0)= -6
, f(2)= Β -12, f(-1)= Β 0, f(6)= 0
2) f(0)= -12
, f(2)= -8
, f(-1)= -14
, f(6)= 168
3) f(0)= 5
, f(2)= Β 20, f(-1)= 2.5
, f(6)= 320
Step-by-step explanation:
1) The given function is f(x) = xΒ² β 5x β 6.
To find the values of Β f(0)
, f(2), Β f(-1), Β f(6) :
Substitute x=0 in f(x) = xΒ² β 5x β 6
f(0) = -6
Therefore, f(0) = -6
Substitute x=2 in f(x) = xΒ² β 5x β 6
f(2) Β = (2)Β² -5(2)-6
β 4-10-6
β 4-16
β -12
Therefore, f(2) = -12
Substitute x= -1 in f(x) = xΒ² β 5x β 6
f(-1) Β = (-1)Β² - 5(-1) -6
β Β 1+5-6
β 6-6
β 0
Therefore, f(-1) Β = 0
Substitute x= 6 in f(x) = xΒ² β 5x β 6
f(6) = (6)Β² - 5(6) -6
β 36 -30 -6
β 36-36
β 0
Therefore, f(6) = 0
2) The given function is f(x) = xΒ³β xΒ²β12.
To find the values of Β f(0)
, f(2), Β f(-1), Β f(6) :
Substitute x=0 in f(x) = xΒ³β xΒ²β12
f(0) = -`12
Therefore, f(0) = -12
Substitute x= 2 in f(x) = xΒ³β xΒ²β12
f(2) Β = (2)Β³ - (2)Β² -12
β 8-4-12
β 8-16
β -8
Therefore, f(2) Β = -8
Substitute x= -1 in f(x) = xΒ³β xΒ²β12
f(-1) Β = (-1)Β³ - (-1)Β² -12
β Β -1-1-12
β -14
Therefore, f(-1) Β = -14
Substitute x= 6 in f(x) = Β xΒ³β xΒ²β12
f(6) = (6)Β³ - (6)Β² -12
β 216 -36 -12
β 216-48
β 168
Therefore, f(6) = 168
3) The given function is f(x) =
To find the values of Β f(0)
, f(2), Β f(-1), Β f(6) :
Substitute x=0 in f(x) =
f(0) = 5 Γ
Any number with power zero is 1.
f(0) = 5
Therefore, f(0) = 5
Substitute x=2 in f(x) =
f(2) = 5 Γ 2Β²
β 5Γ4
β 20
Therefore, f(2) = 20
Substitute x= -1 in f(x) =
f(-1) Β =
β 5 Γ 1/2
β 5 Γ 0.5
β 2.5
Therefore, f(-1) Β = 2.5
Substitute x= 6 in f(x) = Β
f(6) =
β 5 Γ 64
β 320
Therefore, f(6) = 320