If the quadratic equation ax^2 +bx+5=0 where a, b,c are only rational numbers and one of the two solutions is irrational, would the second solution also be irrational? Or would it be rational, or non-real?

i belive those are the ones that are under 90 degreese.

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

x=-2

step-by-step explanation:

28-32x=92

-32x=92-28

-32x=64

x=64/-32

x=-2