What is an equation of the line that passes through the points
(-6, -3)?

The equation of the line that passes through the points (-6,-3) and (0,0) is y= -x/2

Step-by-step explanation:

It is given that,

The line passes through the point (-6, -3).

This point is represented as (x1,y1) which is equal to (-6,3).

The equation of the line can be given in the form y-y1 = m(x-x1).

where,

The slope of the line is given by the formula :

Slope = (y2-y1) / (x2-x1)

Here, there is no other point given in the question.

So, let us assume that the line passes through the origin (0,0) = (x2,y2)

Slope = (0-3) / (0+6) = -3/6

Slope = -1/2

Therefore, m= -1/2

Now, substitute m= -1/2 and x1= -6 and y1 = 3 in the equation of line,

⇒ y-3 = (-1/2) (x+6)

cross multiplying 2 to the left side of equation,

⇒ 2y-6 = -x-6

⇒ 2y = -x-6+6

⇒ y = -x/2

The equation of the line is y= -x/2

go hook jvc hgv cj xk jvc 6756

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: