Mathematics, 17.03.2020 19:13 Travon1418
Solve the system of equations below algebraically.
5x^2 + y^2 - x + 20y - 48 = 0
x-2y+3=0
A) (0,0) and (1, 2)
B) (0, 2)
C) (1, -3)
D) (-3,0) and (1, 2)
Answers: 3
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Solve the system of equations below algebraically.
5x^2 + y^2 - x + 20y - 48 = 0
x-2...
5x^2 + y^2 - x + 20y - 48 = 0
x-2...
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