Type the correct answer in the box. Use numerals instead of words. In the image below, point J is located at the center of the circle, and s is the length of the arc located inside of the triangle. Given that m∠JKL = 94°, m∠KLJ = 41°, and the radius of the circle is 10 units, find s, rounded to the nearest hundredth. s = units

The arc length s is 7.85 units

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the m ∠ KJL

we know that

m ∠ KJL+m ∠ JKL+m ∠ KLJ=180° -----> by the sum of the internal angles of a triangle is 180 degrees

so

m ∠ KJL=180°-(m ∠ JKL+m ∠ KLJ)

m ∠ KJL=180°-(94°+41°)

m ∠ KJL=45°

if m ∠ KJL=45°

then

m arc s=45°------> by central angle

step 2

by proportion

central angle/360°=arc length s/(2*pi*r)

arc length s=(45°/360°)*(2*pi*10)

arc length s=7.85 units

Answer is either b or c

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )