Triangle ABC has a perimeter of 22cm
AB=8cm
BC=5cm
By calculations, deduce whether triangle ABC is a right angled triangle

ΔABC is not a right angled triangle.

Step-by-step explanation:

Perimeter = AB + BC + AC

⇒ AC = 22 - (8 + 5) = 22 - 13 = 9 cm

AC² = AB² + BC²

⇒ AC² = 9² = 81

⇒ AB² + BC² = 8² + 5² = 64 + 25 = 89

∴ AC² ≠ AB² + BC²

⇒ ΔABC is not a right angled triangle.

this is a very good question

step-by-step explanation:

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