The midpoint M of CD¯ has coordinates (−1, 3). Point C has coordinates (−5, 6). What are the coordinates of point D?

The Co-ordinates of D are (3,0)

Step-by-step explanation:

x= x₁ +x₂ /  2        ,     y= y₁+y₂  /2

-1 = -5 + x₂  /2       ,  3 = 6+y₂ /2

Solve them and u ll get the ans

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.