Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 45 employees; the Hawaii plant has 15. A random sample of 10 employees is to be asked to fill out a benefits questionnaire. a. What is the probability that none of the employees in the sample work at the plant in Hawaii?

b. What is the probability that 1 of the employees in the sample works at the plant in Hawaii?

c. What is the probability that 2 or more of the employees in the sample work at the plant in Hawaii?

d. What is the probability that 9 of the employees in the sample work at the plant in Texas?

a) The probability that none of the workers of the sample work in Hawaii is 0.04231

b) The probability that 1 worker of the sample works at the plant in Hawaii is 0.1763

c) The probability that 2 or more employees in the sample work in Hawaii is 0.7814

d) THe probability that 9 of the employees in the sample work at the plant in Texas is 0.1763

Step-by-step explanation:

a) The probability that none of the employeees in the sample work in Hawaii can be computed as follows: First, we have 15 employees in Hawaii from 60 total, so the probability that the employee doesnt work in Hawaii is 45/60. For the second one is 44/59, because we have 1 less case and that is someone in texas. For the third one is 43/58 and so on. Thus, the probability that all 10 workers are not from Hawaii is

45/60*44/59*43/59*42/57*41/56*40/55*39/54*38/53*37/52*36/51 = 0.04231

b) Lets start by computing the probability that the first employee is from Hawaii and the rest now. We have 60 workers, 15 from hawaii, thus, the porbability that the first one is from Hawaii is 15/60 = 1/4. From the remaining 59 workers, 45 are not from Hawaii, therefore, the probability that the second worker is not from Hawaii is 45/59. For the third one the probability is 44/58 and so on, therefore, this probability is

1/4*45/59*44/58*43/57*42/56*41/55*40/54*39/53*38/52*37/51= 0.01763

Since the worker in Hawaii can be any of the 10 in the sample, we should multiply this result for 10 to obtain the probability that exactly 1 worker in the sample works in Hawaii. As a result, the probability that 1 worker of the sample works in Hawaii is 0.01763*10 = 0.1763.

c) The probability that at 0 or 1 workers are from Hawaii is the complementary event of the probability that 2 or more workers in the sample work in Hawaii. Thus, we can obtain this probability by summing the probability that 0 workers are from Hawaii with the probability that 1 workers is from Hawaii and substract that result from 1. Thus, the probability that 2 or more workers work in the plant of Hawaii is 1-(0.1763+0.04231) = 0.7814

d) The event '9 of the employess work at texas' is the exact same event that '1 worker is from Hawaii', therefore the probability of this event is exactly the same than the porbability computed in b), in other words, it is 0.1763

step-by-step explanation:

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation: