Suppose that a "code" consists of 3 digits, none of which is repeated. (A digit is one of the 10 numbers 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.) How many codes are possible?

There are 720 ways of codes are possible.

Explanation:

Given that the code consists of 3 digits, none of which is repeated.

We need to determine the codes that are possible.

The possible ways of codes can be determined using the permutation formula,

where n is the number of choices and r is the number chosen.

Hence, substituting and , we have,

Simplifying, we get,

Cancelling the common terms, we get,

Multiplying, we get,

Thus, there are 720 ways of codes are possible.

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco