I WILL GIVE BRAINLIEST

The polynomial P(x)=x^3−6x^2+6x−23 can be rewritten as P(x)=(x^2+6)(x−6)+13.

Which expression is a factor of P(x)?

a. x^2+6

b. x−6

c. 13

d. none of these

D. None of the above

Step-by-step explanation:

Given the polynomials

P(x)=x³-6x²+6x-23

P(x) can be rewritten as

P(x)=(x²+6)(x−6)+13.

Since, after P(x) was rewritten in

P(x)=(x²+6)(x−6)+13.

So it has a remainder of 13 showing that both (x²+6) and (x-6) is not a factor of the given polynomials.

Also 13 is a constant and not a variable. 13 cannot be factor out of the expression and so it is not even a common factor.

The answer is D, which is none of the above.

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

the answer is two. hope this !