Point p is the center of two concentric circles. pq = 10.5 and ps = 20.9. rs is tangent to the smaller circle and a chord of the larger circle. what is length of rs to the nearest tenth?
36.1
41.8
31.4
41.4

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PRS forms an isosceles triangle with legs = PS=20.9.
Let perpendicular from P to RS meet RS at T.
Then PT is the radius of the smaller circle, 10.5.
From the right-triangle PTS, we find, using Pythagoras,
TS=sqrt(PS^2-PT^2)=sqrt(20.9^2-10.5^2)=18.071 (approx.)
Hence length of chord RS is twice TS, = 36.142