A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 30% of this population prefers the color brown. If 18 buyers are randomly selected, what is the probability that exactly 8 buyers would prefer brown? Round your answer to four decimal places.

0.0811 is the probability that exactly 8 buyers would prefer brown.

Step-by-step explanation:

We are given the following information:

We treat people preferring color brown as a success.

P(prefer color brown) = 30% = 0.30

Then the number of buyers follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 18

We have to evaluate:

0.0811 is the probability that exactly 8 buyers would prefer brown.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

the correct answers i think are b. and d.

give me brainliest if it is correct!