(x-4)^2-28=8 I already got the answer but I will post it anyway because I dont know how to exit out of this screen

Hi there!

The correct answer is 10, -2.

Step-by-step explanation:

you first add 28 on both sides to get: (x-4)^2 = 36

then you square root both sides to get: x-4 = (+/-) 6

then you add four on both sides to get: x = 10, -2

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

sadsdda

step-by-step explanation: