The length of the rectangular garden is 3 m greater than the width. The area of the garden is 88 m squared find the dimensions of the garden
The width of the garden is?
The length of the garden is?

Width = 8m and length = 11m

Step-by-step explanation:

A rectangle is a quadrilateral that is a four sided polygon with two opposite sides parallel and equal.

Let the width be x

Then length = x + 3

Area of a rectangle = length x width

Area = (x+3)(x)

Open bracket

Area = x² + 3x

If area = 88m

Therefore

88 = x² + 3x

x² + 3x - 88 = 0

Solve quadratically using factorisation method by finding two factors of -88 that add up to give 3 the coefficient of x

Factors = 11 and -8 which add up to 3

Rewrite equation

x² + 11x - 8x - 88 = 0

x( x + 11) -8 ( x + 11) = 0

(x -8)(x+11) = 0

x -8 = 0 or x + 11 = 0

x =8 or -11

x = 8m because width can't be negative

Therefore

Length = x + 3

= 8+3 = 11m

Therefore

Width = 8m and length = 11m

I hope this was helpful, please rate as brainliest

easy math just plug in a and b

step-by-step explanation:

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