If secθ = 13\5 and 270° < θ < 360°, then tanθ = . -12\5 -5\12 5\12 12\5

tanΘ = -

Step-by-step explanation:

Using the trigonometric identity

tan²Θ + 1 = sec²Θ, thus

tan²Θ + 1 = ( )² = ( subtract 1 from both sides )

tan²Θ = ( take the square root of both sides )

tanΘ = ±

Since 270 < Θ < 360 , that is the fourth quadrant where tan Θ < 0, thus

tanΘ = -

(23*2)-12=x     x=34

step-by-step explanation: