A corporate Web site contains errors on 50 of 1000 pages. If 100 pages are sampled randomly, without replacement, approximate the probability that at least 2 of the pages in error are in the sample. (Use normal approximation to the binomial distribution.)

The approximate probability that at least 2 pages with errors are in the sample is 0.6406

Step-by-step explanation:

The probability that 1 random page contains errors is 50/1000 = 0.02. Thus, if we take 100 pages, the mean amount of errors is 0.02*100 = 2. The standard deviation will be √2*(1-0.02) = 1.4. Lets call X the number of errors in 100 pages. We can assume that X has normal distribution (otherwise we approximate it to a normal random variable). Lets work with the standarization of X, W, given by

We want to know the probability of X being greater than or equal to 2, for that we will use , the cummulative distribution function of W, whose values can be found in the attached file. We will compute instead the probability of X being greater than 1.5, so that we correct the variable from continuity

The approximate probability that at least 2 of the pages have errors in the sample is 0.6406.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)