Help me please!
A steep road has gradient 4/15. That road rises be 3 meters. Calculate the horizontal distance x

The horizontal distance is 11.25 meters.

Step-by-step explanation:

Step 1:

The gradient of the given road is . The gradient is the ratio of the difference in y values to the difference in x values.

In the given diagram, the difference in y values is given as 3 meters.

The difference in x values is given as x meters.

So if we substitute it with the gradient, we can determine the values of x.

Step 2:

The gradient, by cross-multiplying we get

So the horizontal distance is 11.25 meters.

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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