The acceleration, initial velocity, and initial position of a particle traveling through space are given below. a(t) = (2, −4, −8), v(0) = (−8, 1, 5), r(0) = (15, −2, 4) The particle's trajectory intersects the yz-plane exactly twice. Find these two intersection points. (Order your answers from smallest to largest x, then from smallest to largest y.) (x, y, z) = (x, y, z) =

The intesection points are:

Step-by-step explanation:

The acceleration vector is:

The velocity vector is found by integrating the previous vector as a function of time:

Afterwards, the position vector is constructed by means of integrating velocity  vector:

The particle trajectory intersects the yz-plane when x = 0, then:

The polynomial roots are:

The intesection points are:

answer: okw

step-by-step explanation:

y=mx+