The formula for wind chill (in degrees Fahrenheit) is given byC = 35.74 + 0.6215T ? 35.75v0.16 + 0.4275Tv0.16 where is the wind speed in miles per hour and is the temperature in degrees F. The wind speed is miles per hour and the temperature is 8° ± 3°. Use dC to estimate the maximum possible propagated error and relative error in calculating the wind chill. dC= ± . dC/C= ± .

dC =0.6899T + 30.02

dC/C = (0.6899T + 30.02)/(35.74 + 0.6215T - 35.75V^0.16 + 0.4275Tv^0.16

Step-by-step explanation:

C= 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16

dC = 35.74 + 0.6215T - (35.75×0.16) +:(0.4275×0.16)

dC = 35.74 + 0.6215T - 5.72 + 0.684T

dC = 0.6899T + 30.02

dC/C = (0.6899 + 30.02)/(35.74 + 0.6215T - 35.75Tv^0.16 + 0.4275Tv^0.16

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

answer: sorry i can't you.

step-by-step explanation: