For the distribution of GPAs described in problem 1, what is the probability that a randomly selected student will have a GPA Z score Probability a. less than 3.40 b. less than 3.78 c. more than 3.50 d. more than 2.50 e. between 2.00 and 3.00 f. between 3.00 and 3.50

nope.   happens to me as well.

-aparri

5

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation: