Use z scores to compare the given values. Based on sample data, newborn males have weights with a mean of 3206.5 g and a standard deviation of 724.6 g. Newborn females have weights with a mean of 3024.5 g and a standard deviation of 505.3 g. Who has the weight that is more extreme relative to the group from which they came: a male who weighs 1700 g or a female who weighs 1700 g? Since the z score for the male is zequals nothing and the z score for the female is zequals nothing, the ▼ female male has the weight that is more extreme. (Round to two decimal places.)

Since the z score for the male is z = -2.08 and the z score for the female is z = -2.62, the female has the weight that is more extreme.

Step-by-step explanation:

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Whoever's z-score has the higher absolute value has the weight that is more extreme relative to the group.

Male who weighs 1700 g

Based on sample data, newborn males have weights with a mean of 3206.5 g and a standard deviation of 724.6 g.

This means that

So

The absolute value of the zscore is 2.08

Female who weighs 1700 g

Newborn females have weights with a mean of 3024.5 g and a standard deviation of 505.3 g.

This means that

So

The absolute value of the zscore is 2.62.

So the female has the more extreme weight.

Since the z score for the male is z = -2.08 and the z score for the female is z = -2.62, the female has the weight that is more extreme.

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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