If f(3) = -4, f'(3) = 4, g(3) = 2, and g'(3) = 0, find (f + g)'(3).

(f + g)'(3) = 4

Step-by-step explanation:

If f(3) = -4, f'(3) = 4, g(3) = 2, and g'(3) = 0, find (f + g)'(3).

We should know that:

[f(x) + g(x)]' = f'(x) + g'(x)

So,

(f + g)'(3) = f'(3) + g'(3)

By substitution with f'(3) = 4  and  g'(3) = 0

So,

(f + g)'(3) = f'(3) + g'(3)

              = 4 + 0

∴ (f + g)'(3) = 4

the answer would be c