5. ERROR ANALYSIS Describe and correct the error in finding the sum of the number
(25 x 10"] + 153 x 10" = (25+53) x 110' x 10°)
78 x 10"

  (25 × 10") + 153 × 10" = (25 +153) × 10" = 178 × 10" = 1780"

Step-by-step explanation:

a) Numbers are miscopied: the numbers in parentheses should be (25 +153). Of course, the sum of these should be 178, not 78.

b) The common factor 10" is somehow expanded to 110' x 10°. It should be 10".

The sum should be ...

  (25 × 10") + 153 × 10" = (25 +153) × 10"

  = 178 × 10" = 1780" . . . . . correct sum

Maybe the middle step is an attempt to convert to feet.

  1780" × (1')/(12") = (148 1/3)' = 148' 4"

k

step-by-step explanation:

domit

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)