Find the exact value of csc (theta) for an angle (theta) with cos (theta) = -2/5 and with its terminal side in Quadrant II.

a. sqrt(21)/5

b. -5/2

c. -2/5

d. 5/sqrt(21)

.

Step-by-step explanation:

We are given and that 's angle terminates in quadrant 2 which means .

We will be using Pythagorean Identity: .

Since again 's angle terimates in quadrant 2, we will choose that .

.

d

Step-by-step explanation:

Cosec theta = 1/sin(theta)

Cos²theta + Sin²theta = 1

Sin²theta = 1 - (-⅖)² = 21/25

Sin theta = sqrt(21)/5

Positive because Quadrant 2

Cosec theta = 5/sqrt(21)

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

56

step-by-step explanation: