There is a line that includes the point (-1, -1) and has a slope of 0. What is its equation in slope-intercept form?

y=-1

Step-by-step explanation:

The slope intercept form of a line is

y = mx +b where m is the slope and b is the y intercept

We know the slope is zero

y = 0x+ b

Substituting the values for x=-1 and y=-1 from the point we are given

-1 =0 +b

b=-1

Putting this into the original equation

y = 0x+-1

y=-1

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(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0