How do I find the x and y intercepts from two given points?

(-7,6),(-4,11)

the desired x-intercept is (-53/5, 0); the y-intercept is  (0, 53/3).

Step-by-step explanation:

Find the equation of the line through the given points first:

As we move from (-7,6) to (-4,11), x increases by 3 and y by 5.

Thus, the slope of this line is m = rise / run = 5/3.

Use the slope-intercept formula y = mx + b.  Substitute 5/3 for m, 6 for y and -7 for x:

6 = (5/3)(-7) + b, where b is the y-coordinate of the y-intercept:

6 = -35/3 + b, or 18/3 = -35/3 + b.  Adding 35/3 to both sides, we get:

53/3 = b.

Then the y-intercept is (0, 53/3).

To find the x-intercept, let y = 0 and solve the resulting equatin for x:

0 = (5/3)x + 53/3, or 0 = 5x + 53.  Then x = -53/5, and the desired x-intercept is (-53/5, 0).

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

351°f

step-by-step explanation: