A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the pool walk is 372 square meters more than the area of the pool, find the dimensions of the pool.

x = 26 m is the width of the pool, length: 29+4 = 33 m.

Step-by-step explanation:

We have A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the pool walk is 372 square meters more than the area of the pool.

Let the width of the pool = x

Then the length will = (x+4) ,over all  dimensions will be (x+6) by (x+6+4) or (x+10)

Total area - pool area = 372

∴ x = 26 ft is the width of the pool, length: 29+4 = 33 ft

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

answer: idk wbu

step-by-step explanation: umm..