What is the equation of a line l that has an x-intercept of (5, 0) and is perpendicular to another line m that has a slope -5?
Question 14 options:

y = -5x+ 25

y= -5x + 5

y = 1/5 x + 5

y = 1/5 x - 1

Step-by-step explanation:

Slope of a perpendicular line is the "negative reciprocal" of the slope of the original line (i.e )

∴  

the slope-intercept form:

with

and

is

c: lkllmn.

hope it's you

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15