Write the equation of the line through (--6, +-2) and (-7,-5)
must be very detailed use formula and graphing

y = 3x + 16

Step-by-step explanation:

write the equation of the line through (-6 , -2) and (-7,-5)

The general form of the line is  y = mx + c

Where m is the slope and c is the y-intercept

The slope m = (y₂ - y₁)/(x₂ - x₁) = (-5 - [-2])/(-7 - [-6]) = (-3)/(-1) = 3

∴ y = 3x + c

By substitution with the point (-7,-5) to find c

So, at x = -7 ⇒ y =-5

-5 = 3 * -7 + c

-5 = -21 + c

c = -5 + 21 = 16

∴ y = 3x + 16

See the attached figure which represents the graph of the line y = 3x + 16

the answer i think is a)

step-by-step explanation:

show us the graphs dude

step-by-step explanation: