Solve the following equation.
6cos²x - 7cosx + 1 = 0, for
0° ≤ x ≤ 360°

For 0° ≤ x ≤ 360° we have:

x=0, 360, arccos(1/6), -arccos(1/6)

Step-by-step explanation:

Replace cos(x) by y

6y²-7y+1=0

6y²-6y-y+1=0

6y(y-1) -(y-1)=0

(y-1)(6y-1)=0

Roots:

y=1, cos(x)=1, x=0 and 360

y=1/6, cos(x)=1/6, x=arccos(1/6) and x=-arccos(1/6)

Step-by-step explanation:

step-by-step explanation:

which of the following statements correctly describes the expression below based on its degree and number of terms?

314 - 7x2 + 11