The vertices of a polygon are P(0,4), Q(5,4), R(5-3) and S(0,-3). What is the perimeter of the polygon? (Show work please)

The perimeter of the polygon are

PQ = 5

RS = 5

PR = √74 = 8.60

QS = √74 = 8.60

QR = 7

Step-by-step explanation:

To calculate the perimeter of a polygon, polygon is like a coordinate with points, to find the length, we use this formula

d = √(x _2 - x_1)^2 + (y_2 - y_1)^2

Let's start from the first two vertices P ( 0 , 4) and Q(5 , 4)

x_1 = 0

y_1 = 4

x_2 = 5

y_2 = 4

PQ = √ ( 5 - 0)^2 + ( 4 - 4)^2

= √ 5^2 + 0^2

= √ 25

= 5

Between R( 5 , -3) and S ( 0 , -3)

x_1 = 5

y_1 = -3

x_2 = 0

y_2 = -3

RS = √ ( 0 - 5)^2 + ( -3 - (-3))^2

= √( -5)^2 + ( -3 + 3)^2

= √ 25 + 0

= √ 25

= 5

Between P( 0 , 4) and R (5 , -3)

x_1 = 0

y_1 = 4

x_2 = 5

y_2 = -3

PR = √( 5 - 0)^2 + ( -3 - 4)^2

= √ 5^2 + (-7)^2

= √ 25 + 49

= √ 74

= 8.60

Between Q ( 5 , 4) and S(0 ,-3)

x_1 = 5

y_1 = 4

x_2 = 0

y_2 = -3

QS = √ ( 0 - 5)^2 + ( -3 - 4)^2

= √ -5^2 + -7^2

= √ 25 + 49

= √ 74

= 8.60

Between Q( 5,4) and R(5 , -3)

x_1 = 5

y_1 = 4

x_2 = 5

y_2 = -3

QR = √ (5 - 5)^2 + ( -3 - 4)^2

= √ 0^2 + (-7)^2

= √ 0 + 49

= √ 49

= 7

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9