Mathematics, 14.03.2020 22:54 statonglenda

Two ropes are attached to a large ballon in a parade. The people holding the ropes are 40 feet apart, and the angle between the two ropes is 86 degrees. The angle of elevation of one rope is 42 degrees. How long is each rope..Step by Step explanation..Please ..Thanks.

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Answer from: laylaaaaah1603

Length of one side of rope is 31.5958 feet and length of other side is 26.828 feet

Step-by-step explanation:

We are given distance between ropes = 40 feet

Angle between two ropes = 86 degrees

Angle of elevation of one rope = 42 degrees

We need to find the length of both ropes

First finding angle of elevation of 2nd rope:

180 - (86+42)=Angle of elevation of 2nd rope

Angle of elevation of 2nd rope = 52 degrees

Now finding sides of rope (see reference of figure attached)

Using Law of Sines:

$\frac{Sin(C)}{c}=\frac{Sin(B)}{b}$

Putting values of angle C and B and side c to find side

$\frac{sin(86)}{40}=\frac{sin(52)}{b} \\b(sin(86)=40(sin(52))$

$b(0.9976)=40(0.7880)\\b(0.9976)=31.52\\b=\frac{31.52}{0.9976}\\b=31.5958\,\,feet$

So, Length of side b is 31.5958 feet

Similarly finding length of side a

Using Law of Sines:

$\frac{Sin(A)}{a}=\frac{Sin(C)}{c}$

Putting values of angle C and B and side c to find side

$\frac{sin(42)}{a}=\frac{sin(86)}{40} \\40(sin(42)=a(sin(86))$

$40(0.6691)=a(0.9976)\\26.764=a(0.9976)\\a=\frac{26.764}{0.9976}\\a=26.828\,\,feet$

So, length of side a is 26.828 feet

Therefore, length of one side of rope is 31.5958 feet and length of other side is 26.828 feet

Two ropes are attached to a large ballon in a parade. The people holding the ropes are 40 feet apart

Answer from: Quest

Wednesday1.) < 2.) 1961015.)6.486.)68.761 can be rounded up to 69i can't truly see the rest and my next comment will be thursday
Me with wendsday and thursday questions going straight down show work you

Me with wendsday and thursday questions going straight down show work you

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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