A merchant borrowed Rs. 2000 from two money lenders. For one loan, he paid the interest at
8% per annum and for the other 6% per annum. The total
interest paid for one year was Rs. 135. How much did he
borrow at each rate?

Solution:

A merchant borrowed Rs. 2000 from two money lenders

Let the sum at 8 % be x

Then, the sum at 6 % be 2000 - x

The total  interest paid for one year was Rs. 135

8 % of x + 6 % of (2000 - x) = 135

Divide both sides by 0.02

x = 750

Then,

2000 - x = 1250

Thus, Rs 750 was borrowed at 8 % interest rate and Rs 1250 was borrowed at 6 % interest rate

your answer is a

step-by-step explanation:

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34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm